2025-08-23 15:30:08 +0000 UTC
Find the Minimum Area to Cover All Ones II
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class Solution:
def minimumSum2(
self, grid: List[List[int]], u: int, d: int, l: int, r: int
) -> int:
min_i = len(grid)
max_i = 0
min_j = len(grid[0])
max_j = 0
for i in range(u, d + 1):
for j in range(l, r + 1):
if grid[i][j] == 1:
min_i = min(min_i, i)
min_j = min(min_j, j)
max_i = max(max_i, i)
max_j = max(max_j, j)
return (
(max_i - min_i + 1) * (max_j - min_j + 1)
if min_i <= max_i
else sys.maxsize // 3
)
def rotate(self, vec: List[List[int]]) -> List[List[int]]:
n = len(vec)
m = len(vec[0]) if n > 0 else 0
ret = [[0] * n for _ in range(m)]
for i in range(n):
for j in range(m):
ret[m - j - 1][i] = vec[i][j]
return ret
def solve(self, grid: List[List[int]]) -> int:
n = len(grid)
m = len(grid[0]) if n > 0 else 0
res = n * m
for i in range(n - 1):
for j in range(m - 1):
res = min(
res,
self.minimumSum2(grid, 0, i, 0, m - 1)
+ self.minimumSum2(grid, i + 1, n - 1, 0, j)
+ self.minimumSum2(grid, i + 1, n - 1, j + 1, m - 1),
)
res = min(
res,
self.minimumSum2(grid, 0, i, 0, j)
+ self.minimumSum2(grid, 0, i, j + 1, m - 1)
+ self.minimumSum2(grid, i + 1, n - 1, 0, m - 1),
)
for i in range(n - 2):
for j in range(i + 1, n - 1):
res = min(
res,
self.minimumSum2(grid, 0, i, 0, m - 1)
+ self.minimumSum2(grid, i + 1, j, 0, m - 1)
+ self.minimumSum2(grid, j + 1, n - 1, 0, m - 1),
)
return res
def minimumSum(self, grid: List[List[int]]) -> int:
rgrid = self.rotate(grid)
return min(self.solve(grid), self.solve(rgrid))