2025-08-22 15:30:44 +0000 UTC
Minimum Number of Pushes to Type Word I
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class Solution:
def minimumPushes(self, word: str) -> int:
freqs = [0] * 26
for char in word:
freqs[ord(char) - 97] += 1
freqs.sort()
cost = 1
res = 0
while freqs and freqs[-1] != 0:
for _ in range(8):
if not freqs:
break
freq = freqs.pop()
if freq == 0:
break
res += freq * cost
cost += 1
return res