2025-08-22 10:58:21 +0000 UTC
Maximum Strong Pair XOR I
Categories:
Links
Code
class Solution:
def maximumStrongPairXor(self, nums: List[int]) -> int:
max_xor = 0
for num1, num2 in itertools.permutations(nums, 2):
if abs(num2 - num1) <= min(num1, num2):
max_xor = max(max_xor, num1 ^ num2)
return max_xor