2025-08-21 08:45:30 +0000 UTC
Minimum Seconds to Equalize a Circular Array
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class Solution:
def minimumSeconds(self, nums: List[int]) -> int:
nums += nums
indices = defaultdict(list)
for i, num in enumerate(nums):
indices[num].append(i)
min_diff = math.inf
for idxs in indices.values():
max_diff = -math.inf
for i1, i2 in itertools.pairwise(idxs):
max_diff = max(max_diff, i2 - i1)
min_diff = min(min_diff, max_diff // 2)
return min_diff