2025-08-19 16:47:47 +0000 UTC
Remove Letter To Equalize Frequency
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Code
class Solution:
def equalFrequency(self, word: str) -> bool:
freqs1, freqs2 = defaultdict(int), defaultdict(int)
for char in word:
freqs1[char] += 1
for freq in freqs1.values():
freqs2[freq] += 1
if len(freqs2) == 1:
return next(iter(freqs2.keys())) == 1 or next(iter(freqs2.values())) == 1
if len(freqs2) == 2:
f1, f2 = min(freqs2.keys()), max(freqs2.keys())
return (
f1 + 1 == f2 and freqs2[f2] == 1
) or (
f1 == 1 and freqs2[f1] == 1
)
return False