2023-07-23 16:55:42 +0000 UTC
Middle of the Linked List
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Code
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def middleNode(self, head: Optional[ListNode]) -> Optional[ListNode]:
middle = head.next if head else None
tail = middle.next if middle else None
move = True
while tail and tail.next:
tail = tail.next
if move:
middle = middle.next
move = not move
return middle if middle else head