2023-08-23 09:45:05 +0000 UTC
Reorganize String
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Code
class Solution:
def reorganizeString(self, s: str) -> str:
result = []
# Min heap ordered by character counts, so we will use
# negative values for count
priority_queue = [(-count, char) for char, count in Counter(s).items()]
heapify(priority_queue)
while priority_queue:
count_first, char_first = heappop(priority_queue)
if not result or char_first != result[-1]:
result.append(char_first)
if count_first != -1:
heappush(priority_queue, (count_first + 1, char_first))
continue
if not priority_queue:
return ""
count_second, char_second = heappop(priority_queue)
result.append(char_second)
if count_second != -1:
heappush(priority_queue, (count_second + 1, char_second))
heappush(priority_queue, (count_first, char_first))
return "".join(result)