2025-07-30 17:27:09 +0000 UTC

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def mergeTrees(self, root1: Optional[TreeNode], root2: Optional[TreeNode]) -> Optional[TreeNode]:
        def dfs(node1: Optional[TreeNode], node2: Optional[TreeNode]) -> None:
            if node1 is None:
                return node2
            if node2 is None:
                return node1
            node1.val += node2.val
            node1.left = dfs(node1.left, node2.left)
            node1.right = dfs(node1.right, node2.right)
            return node1
        
        return dfs(root1, root2)