2023-12-11 12:30:35 +0000 UTC
Keyboard Row
Categories:
Links
Code
class Solution:
def findWords(self, words: List[str]) -> List[str]:
ans = []
rows = [
set("qwertyuiop"),
set("asdfghjkl"),
set("zxcvbnm")
]
for word in words:
for row in rows:
if len(row.union(word.lower())) == len(row):
ans.append(word)
break
return ans