2025-08-01 16:27:17 +0000 UTC

N-Repeated Element in Size 2N Array
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Code

class Solution:
    def repeatedNTimes(self, nums: List[int]) -> int:
        length = len(nums)
        for k in range(1, 4):
            for i in range(length - k):
                if nums[i] == nums[i+k]:
                    return nums[i]
        raise Exception