2023-09-23 18:54:59 +0000 UTC
Remove Nth Node From End of List
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# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def removeNthFromEnd(self, head: Optional[ListNode], n: int) -> Optional[ListNode]:
cur_length, target_length, before_removed = 0, n + 1, head
tail = head
while tail and cur_length != target_length:
tail = tail.next
cur_length += 1
if not tail and cur_length != target_length:
return head.next
while tail:
before_removed = before_removed.next
tail = tail.next
before_removed.next = before_removed.next.next
return head