2024-05-27 07:56:18 +0000 UTC
Special Array With X Elements Greater Than or Equal X
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class Solution:
def specialArray(self, nums: list[int]) -> int:
nums.sort()
n: int = len(nums)
def find_number_of_nums(cur_num) -> int:
left: int = 0
right: int = n - 1
first_index: int = n
while left <= right:
mid: int = (left + right) // 2
if nums[mid] >= cur_num:
first_index = mid
right = mid - 1
else:
left = mid + 1
return n - first_index
for candidate_number in range(1, n + 1, 1):
if candidate_number == find_number_of_nums(candidate_number):
return candidate_number
return -1