2023-07-16 09:53:42 +0000 UTC

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def hasCycle(self, head: Optional[ListNode]) -> bool:
        slow_p, fast_p = head, head.next if head else None
        while fast_p and fast_p.next:
            if slow_p == fast_p:
                return True
            slow_p, fast_p = slow_p.next, fast_p.next.next

        return False