2024-06-22 13:33:20 +0000 UTC
Count Number of Nice Subarrays
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Code
class Solution:
def numberOfSubarrays(self, nums: List[int], k: int) -> int:
for i in range(len(nums)):
nums[i] %= 2
prefix_count = [0] * (len(nums) + 1)
prefix_count[0] = 1
s = 0
ans = 0
for num in nums:
s += num
if s >= k:
ans += prefix_count[s - k]
prefix_count[s] += 1
return ans